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4x^2-24x-540=0
a = 4; b = -24; c = -540;
Δ = b2-4ac
Δ = -242-4·4·(-540)
Δ = 9216
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{9216}=96$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-24)-96}{2*4}=\frac{-72}{8} =-9 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-24)+96}{2*4}=\frac{120}{8} =15 $
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